4x^2-25/2x^2-3x-5

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Solution for 4x^2-25/2x^2-3x-5 equation: 


x in (-oo:+oo)

4*x^2-((25/2)*x^2)-(3*x)-5 = 0

4*x^2+(-25/2)*x^2-3*x-5 = 0

-17/2*x^2-3*x-5 = 0

DELTA = (-3)^2-(-17/2*(-5)*4)

DELTA = -161

DELTA < 0

x belongs to the empty set

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